# Thread: Big Cube BLD Discussion

1. Chris could you possibly make a complete tutorial on this subject and put it in your website and can you try to make the format like Joel Van Noort's website please? it's just an opinion i hope youthink about it thanks very much

2. Originally Posted by xXzaKerXx
Chris could you possibly make a complete tutorial on this subject and put it in your website and can you try to make the format like Joel Van Noort's website please? it's just an opinion i hope youthink about it thanks very much
I can't find right now, but there is a thread in which Chris explainied a BLD method of his in this forum.

3. Originally Posted by cmhardw
Originally Posted by siva.shanmukh
That will add some moves to it. Won't be 9 anymore. Anyways is it something this:

y U' r' f r' f' r2 U y'
Wow, no your alg is much more efficient at the pseudo-cycle than mine. My pseudo cycle was:
U' r U2 f' U2 r' U2 f U'

Anyways I liked dbeyer's version : written in SABA'B'S' form
S: U x
A: uR2u'
B: r'
Yes but it is a 10 mover :-P Daniel and I were just talking to try and see which strategy would be more fruitful: try to prove there does not exist a 9 mover for this case somehow, or, hopefully, discover something amazing that only takes 9 moves to solve this case!

Chris
Oh, just realized that you are not counting the cube rotations(makes sense)
That makes my pseudo cycle 7 moves long right?
Now to stop the other 3 cycles, I replaced the f and f' with U' f U and U' f' U respectively making it 11 move

y U' r' U' f U r' U' f' U r2 U y'

4. Chris, that is the alg I found. Haha, yeah, great minds think alike I suppose.
All this algorithm does on a 3x3 is move the 6 centers of the core about the solved 3x3 cube. We are breaking the 3x3 core into 4 quadrants per face, and doing a few setups for the same effect on the 4x4.
Adding some extra moves too because we are trying to move certain pieces.

Okie doke gonna think on this. I have a competition tomorrow. Wish me luck Chris.

Later,
DB

5. ## 5x5x5 BLD Parity?

I just did a 5x5x5 BLD. This is the first time I do it again after my first successful solve about 2 months ago. On my first 5x5x5 BLD, I didn't got any odd target, so I hadn't encountered any 5x5x5 BLD parity.

But I had it on this solve, which was hand-scrambled by me.

I got the breakdowns:

1. Memo x centers: 03:04.10
2. Memo + centers: 03:42.40
3. Memo middle edges: 01:14.30
4. Memo wing edges: 02:21.40
5. Memo corners: 00:52.30
6. Refresh all: 04:36.30
7. Execution: 18:09.00
(too bad I didn't timed each execution steps)

TOTAL 33:59.90 (15:50.80).

It could've been my new PB by 38 seconds, but it's not , because I got this:

[My BLD scheme is Red on Front & Yellow on Top, BOY]

FYI, I use M2 for middle edges, r2 for wing edges, and Classic Pochmann for corners. These are the detailed execution steps:

1. Solve x centers
2. Solve + centers
3. Solve middle edges > odd items/parity (fixed it with U'F2U M2 U'F2U)
4. Solve wing edges > even items/no parity
5. Solve corners > odd items/parity (no fixing)

So, where did I made mistake?
I'm very very sure I memorized all items correctly.

Please, I hope anyone would kindly help me.
Thank you.

6. probably when fixing middle layer edges parity, you forgot to "fix back" wings?

7. I never do a sighted solve with 5x5x5...

How do we fix back wings?

8. umm, like: you do a J perm to fix corner-edge parity, but this way, you swap the 2-2 wings like on your latest attempt. in this case you just have to set them so they're diagonal (for example: if the blue is the R on the picture, then: RUR'), and do an 5x5-safe PLL parity, like:
(y, then) Rw2 Fw2 U2 r2 U2 Fw2 Rw2 or
(y, then) r2 U2 r U2 r2 U2 r2 U2 r U2 r2 U2
and after this, you just have to undo the setup.
I hope this solves your problem also I hope I understood the problem and could answer it correctly

9. Yes, I suspect that's the problem. Since I do it differently, it's hard for me to be specific to your case. When I do corner parity on 5x5x5, I always use a T-perm, swapping opposite edges with the corners. Then I do Bw2 Rw2 U2 b2 U2 Rw2 Bw2 to correct the edges.

10. my parity on the 5x5 is like: (corners: hungarian version of pochmann, freestyle, 3op, whichever is the easiest, when I get parity I always keep UFR and UBR swapped, and M2 for edges)
so, I end up with UB-DF swapped, and UFR-UBR. what I do is:
F2, then Rw2 U2 Rw U2 Rw2 U2 Rw2 U2 Rw U2 Rw2 (which does a pll parity on UF-UB, and as a side effect, does a H perm) F2, then a T perm. I find it quite handy

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