1. Originally Posted by JianhanC
3OP corners is actually a subset of BH corners, except that it has a buffer piece. If you have a cycle that has more than 3 corners, you memorise the corners in pairs. For example, you have a cycle F > E > B > Q > T > J. You memorise FE, because the piece in the buffer position has to go to F, and the piece in F has to go to E. And the piece in E will go back to the buffer piece. Then the next cycle. The piece in the buffer now has to go to B, and the one in B has to go to Q, so after FE comes BQ, and so on.

If you have a 2 cycle left, you should probably set it up into a PLL. Just remember to orient the corners and make sure they are in the same layer. If your buffer is already solved, 'store' it in another spot, lets say R. Then when you come across the piece that belongs in R you know you're done. I hope this made sense.
thank a lot (zane+Jianhan) C. it made lots of sense. i can't find an optimal way to set up 2 corners into a Pll and orient it, i hope can u give me an example about that

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2. Say URB-> DRF-> ULB.

D' F2 (A-perm) F2 D

3. The original intent of the method was to always end the same way.
I used a small algorithm set to solve parity. My set up was always 1 move.

Swapping both buffers w/ a random cubie leaves to many possibilities. So, I made sure to hold the Edge swap constant. For example, my buffers were UR and URB. I would always swap UR and UB for my edge cycle. The URB swaps randomly with XYZ. This works by adding one last cycle.

For example, UR ->XY -> UB for my last cycle. This leaves UR and UB swapped. Next, swapping URB w/ XYZ is easy. Use the algorithms I have provided 3 ... maybe 5 years ago.

The cycle of edges is easier than figuring out a setup on the fly. Also, less time undoing the setup at the end of the solve. Bam, done. Rather than oh Geeze, how did I set this one up again?!

4. Originally Posted by jonlin
Say URB-> DRF-> ULB.

D' F2 (A-perm) F2 D
R2 D'L2D R2 D'L2D
Or maybe BLB' R2 BL'B' R2

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