I am trying to learn to solve the 5x5x5, and am primarily using Andy Klise's guide at http://www.kungfoomanchu.com/ , with help from some other sources online and my own methods I already use to solve the 3x3x3 and 4x4x4.
I am stuck at joining the last two edges.
Klise's guide is comprehensive for all cases with the last two edges, but I must be reading something wrong, because the algorithms don't seem to be accomplishing the result I expect. I may be misunderstanding the notation; I thought that I understood cube notation, but there are a couple of things in his guide that seem different from what I thought I knew.
I read some of the sticky threads here; one included a link to a notation site which seems to be down: http://solvethecube.110mb.com/notation.html , and one included a link to the wiki which provides a helpful notation page that clears up a couple of things I didn't understand, but still doesn't seem to answer all my questions.
For starters, what do the parentheses mean in this algorithm?
x' d (R F') U (R' F) d'
Because when I work this algorithm it doesn't seem at all to do what I think it should do. I tried the variant beneath and that doesn't seem to do anything different.
Second question: for this algorithm, one face of the cube is displayed: is that supposed to be the top of the cube, or the front? Because no matter how I position it, the algorithm seems to affect edges over on the side of the cube, away from where I expect. I discovered that version 2 of Klise's guide is still reachable on his site (the current edition is version 3), and it displays these cases differently, suggesting that the unjoined edges go on the front face, and displaying the algorithm without any cube rotations, but the algorithm still does not seem to work, moving from one last-two-edges-case to another rather than finishing the last two edges.
I am probably missing something that would be obvious to a much more experienced cuber. I came here for help because Klise's guides link to a thread here. I've searched and found a couple of threads discussing his guides, but nothing indicating anybody else has had this problem, so I am certain that I am just misunderstanding something about the notation, but I can't find anything here or with Google that is clearing this up for me.
d R U R' F R F' R' d'
1. The parenthesis don't have any real function, apart from highlighting a sequence of moves that is repeated in one way or another in the algorithm. In the example you give the R F' is repeated as R' F after a U turn.
2. The picture doesn't represent a face, but the last two unsolved tredges. So when you have all tredges paired up and are left with two tredges, you put them opposite each other and look up which case it is and what algorithm goes with it.
Last edited by hcfong; 04-26-2012 at 10:52 AM.
Can you do the ELL?
First off: I'm a totally bloody noob and even though i know more than 2 days before, i can hardly make heads nor tails from hints that were giben to me...
Let's assume i have solved one layer of a 2x2x2 on my own and now i want to solve it completely.
How do i have to orientate it and what algorythms do i use based on the orientation of what tile?
Regarding the guide: What do the brackets mean and what if the algorithms are in separate brackets?
How do i have the read the entries beside the depictations of the cube to know what to do?
Question one: Yeah, that's what i understood from the beginning, i just don't get what to make of something like THIS:
My case would the very first one of the Ortega method:
(R U R' U)(R U2' R')
y' (R' U2)(R U R' U R)
But where does the yellow side have to face when i execute the algorythms?
Do i have to pay attention to certain other things?
There are 2 errors in the CLL (2x2) pdf:
(1) Antisune, 4th case: x'U'RUR'F2R'F2R (Cameron Stollery);
(2) Antisune, 6th case: xURU'x'URU'RUR'UR' (Cameron Stollery).
That's too bad, they seem great, and the second one is the last CLL algorithm left to me to learn! .
Anyway, thanks a lot Andy! I managed to learn the CLL easily with your page. Before, I was using Layer By Layer method, averaging 6-7 seconds. Now I'm averaging 10 seconds with CLL (I just learnt them, recognition is still bad), but hopefully my times will drop quickly!
Last edited by kalyk; 03-17-2013 at 06:06 AM.
It is pretty much just the normal algs but the cases are organized in a logical manner
I have tried to find the error in those two cases that you mentioned, but can't find one. Both cases require a rotation on the x axis before performing the alg, maybe that is what was causing the confusion. Maybe also make sure you are using the most recent version of the guide, located here: http://www.kungfoomanchu.com/#2x2x2cll Let me know if things are still going awry